Modern 2:Probability Currents
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On Wednesday we will describe a number of scattering and bound-state problems. Try to set up, | On Wednesday we will describe a number of scattering and bound-state problems. Try to set up, | ||
| − | on your own, the solution of the Schrodinger for a square well potential. I.e., V(x) = 0 for | + | on your own, the solution of the Schrodinger for a square well potential. I.e., <math>V(x) = 0 \hbox{ for } |
| − | x < 0 and x> a. And <math>V(x) = -V_0 \hbox{for} 0 leq x \leq a </math> | + | x < 0 \hbox{ and } x> a</math>. And <math>V(x) = -V_0 \hbox{ for } 0 \leq x \leq a </math> |
Revision as of 17:34, 6 March 2006
I will go through section 3.5 on The Probability Current.
On Wednesday we will describe a number of scattering and bound-state problems. Try to set up,
on your own, the solution of the Schrodinger for a square well potential. I.e., V(x) = 0 for x < 0 and x > a. And 
