HW 8

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1) The Fourier series of a Sin function should be trivial, right? Execute the following Mathematica code.  Explain the result.g[x_] =
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1) The Fourier series of a Sin function should be trivial, right? Execute the following Mathematica code.  Explain the result.
 
  FourierTrigSeries[Sin[x], x, 4]
 
  FourierTrigSeries[Sin[x], x, 4]
  
 
Remember to load the appropriate library before you try this.
 
Remember to load the appropriate library before you try this.
  
2) Look at problem 5.2 in Chapter 7 of Boas.  Verify the first nonzero Sin and Cosine terms by doing the integrals by hand.  Then show me the precise call to FourierTrigSerries that will reproduce the 8 terms shown in the answer.
+
2) Look at problem 5.2 in Chapter 7 of Boas.  Verify the first nonzero Sin and Cosine terms by doing the integrals by hand.  Then show the precise call to FourierTrigSeries that will reproduce the 8 terms shown in the answer.  This will require to look carefully into the definitions used by Mathematica and the optional arguments of FourierTrigSeries.
  
 
3-4) Chapter 7, section 10 of Boas:  Problems 4 and 9.
 
3-4) Chapter 7, section 10 of Boas:  Problems 4 and 9.
  
 
5) Prove Equation 11.5 on page 375.
 
5) Prove Equation 11.5 on page 375.
 +
 +
6) Show that this function is ''normalized''.  That means that when you integrate it from
 +
-infinity to +infinity you get 1: 
 +
 +
<math>\frac{1}{\sqrt{2 \pi} \sigma} e^{(-(t - m)^2/(2 \sigma^2))} </math>
 +
 +
7) Show that the Fourier transform of this function is:
 +
<math>\frac{e^{i m w-\frac{w^2 \sigma ^2}{2}}}{\sqrt{2 \pi }}</math>
 +
 +
Thus, the Fourier transform of a Gaussian is not a Gaussian itself unless the mean is zero.

Latest revision as of 19:21, 28 October 2007

1) The Fourier series of a Sin function should be trivial, right? Execute the following Mathematica code. Explain the result.

FourierTrigSeries[Sin[x], x, 4]

Remember to load the appropriate library before you try this.

2) Look at problem 5.2 in Chapter 7 of Boas. Verify the first nonzero Sin and Cosine terms by doing the integrals by hand. Then show the precise call to FourierTrigSeries that will reproduce the 8 terms shown in the answer. This will require to look carefully into the definitions used by Mathematica and the optional arguments of FourierTrigSeries.

3-4) Chapter 7, section 10 of Boas: Problems 4 and 9.

5) Prove Equation 11.5 on page 375.

6) Show that this function is normalized. That means that when you integrate it from -infinity to +infinity you get 1:

\frac{1}{\sqrt{2 \pi} \sigma} e^{(-(t - m)^2/(2 \sigma^2))}

7) Show that the Fourier transform of this function is: \frac{e^{i m w-\frac{w^2 \sigma ^2}{2}}}{\sqrt{2 \pi }}

Thus, the Fourier transform of a Gaussian is not a Gaussian itself unless the mean is zero.

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