Exam 1 preparation

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<math>\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2</math>
 
<math>\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2</math>
  
# Let <math> A = \begin{Bmatrix} a & b \\ c & d \end{Bmatrix} </math>
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# Let <math> A = \begin{matrix} a & b \\ c & d \end{matrix} </math>

Revision as of 16:03, 5 October 2006

The exam will consist of 4 questions from which you must choose 3 to do.

It will be open book and 50 minutes in length.

Here are practice problems.

  1. Use the McClaurin series expansion of \cos(x) \, to thow that

\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2

  1. Let  A = \begin{matrix} a & b \\ c & d \end{matrix}
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