Exam 1 preparation

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<math>\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2</math>
 
<math>\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2</math>
  
#<math> Let A =  
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# Let <math> A = \begin{pmatrix} a & b \\ c & d \end{pmatrix} </math>
\begin{pmatrix}
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a & b \\
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c & d
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\end{pmatrix}
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</math>
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Revision as of 16:02, 5 October 2006

The exam will consist of 4 questions from which you must choose 3 to do.

It will be open book and 50 minutes in length.

Here are practice problems.

  1. Use the McClaurin series expansion of \cos(x) \, to thow that

\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2

  1. Let  A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}
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