Exam 1 preparation

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<math>\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2</math>
 
<math>\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2</math>
 +
 +
#<math> Let A =
 +
\left[
 +
\begin{array}{cc}
 +
a & b \\
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c & d
 +
\end{array}
 +
\right]</math>

Revision as of 15:56, 5 October 2006

The exam will consist of 4 questions from which you must choose 3 to do.

It will be open book and 50 minutes in length.

Here are practice problems.

  1. Use the McClaurin series expansion of \cos(x) \, to thow that

\lim _ {x \rightarrow \infty} \frac{1 - \cos(x)}{x^2} = 1/2

  1.  Let A = 
\left[
\begin{array}{cc}
a & b \\
c & d
\end{array}
\right]
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